https://projecteuler.net/problem=1

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

use v6;



(1..^1000).grep({ ! ($^a % 3 and $^a % 5) }).reduce({ $^a + $^b }).say;

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